The sampling distribution of the proportion p̂.
Mean equal to population proportion p.
Standard deviation equal to √[p(1-p)/n]
which is approximately normal provided that np and n(1-p) are large enough (5 or 10).
Standard normal pop. μ=0. σ=1 N=100,000 10,000 samples of n=10 --> σx̄≈ .32 10,000 samples of n=100 --> σx̄≈ .1 Uniform pop. [0,100] μ=50. σ=29 N=100,000 10,000 samples of n=10 --> σx̄≈ 9.2 range~20-80 10,000 samples of n=100 --> σx̄≈ 2.9 range~40-60 Exponential pop. λ=.1 μ=10. σ=10 N=100,000 10,000 samples of n=10 --> σx̄≈ 3.16 range~2-27 10,000 samples of n=100 --> σx̄≈ 1 range~7-14